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Author
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Topic: Anyone seen this plane??? | Topic page views:
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Dirk Digler
Senior Member
126 posts, Mar 2001
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posted 03-24-2001 01:26 PM
3T3L1,i think you are still missing my point. it doesnt matter what the distance is to the hill. you need the distance to the point directly below the contrail. the hill is irrelevent just as the distance to a building is irrelevent when considering the sun. those trails could be, and probably are miles behind the hill. refer to CY's above post. do you know the distance to the trail?
[Edited 1 times, lastly by Dirk Digler on 03-24-2001] 
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mark sky
bin Rydin

SW coast of Oregon 1089 posts, Jun 2001
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posted 03-24-2001 02:11 PM
Well i see that several pilots have gone to some trouble to explain these pictures as normal, but I also see that the implications have been understood. I have read Dr. Minnis's study on contrail formation, and it is highly unlikely that contrails would have formed on this day at all, and if they had formed they would have been very brief in duration and been formed above 35000' elevation. I suppose you will now counter with "You dont provide thus in such atmosperic readings at the time", and "Minnus says contrails can turn into persistant cirrus cloud" and so forth. But don't bother as i will say it for you. The thing is, if these trails were contrails (formed at 35000'), from the distances i have given you, they would have to be 60 miles away, and obviously they are not 60 miles away. Think about a town 60 miles from where you live, imagine contrails over them, and how they might look.. To answer a few other questions, I have been told (by the FAA) that i indeed live in an MOA (Military Operations Area) and that there are no commercial flights over my area. I was told by Chickie Deb that she saw no commercial flights within 70 miles of the oregon coast showing up on Flight Explorer. I have witness a tremendouse amount of jet traffic in this coastal MOA zone, and most of the planes seem to be in need of engine repairs (they intermittantly smoke) just a joke guys~you don't have to dignify that with a long drawn out responce about how normal it all is, because you know, it is really simple YOU BELIEVE everything is NORMAL and EXPLAINABLE and I BELIEVE something very abnormal is occuring and we just burn up time trying to make the other side PROVE IT I am not going to convince you, or you me. have a nice saturday
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3T3L1
Differentiated Mouse Fibroblasts

Lubbock, Texas 1347 posts, Mar 2001
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posted 03-24-2001 02:40 PM
You're right, Mark. Enough said.Dirk, please take a geometry course before you do any more flying. Thanks. 
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cydoniaquest
nobody
nowhere 803 posts, Aug 2000
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posted 03-24-2001 03:10 PM
I could be wrong marksky, but I don’t think anyone is trying to explain your photo as “normal”....just eliminate the possibilities based on our individual perspectives and experiences. Dirk and I immediately thought of the possibility of holding patterns based on the perspectives of a commercial and civilian pilot. “Top Gun”, of course, has a military perspective and gave a more detailed opinion of what these could be based on his unique experience as a fighter pilot. It seems to me then, given that these photos were taken within an MOA as you have now confirmed, Top Gun may indeed have the most accurate perspective and probable explanation here.Rather than drifting apart in our respective opinions, it seems to me we have come to a common denominator....that these trails were most probably laid by military aircraft performing maneuvers. Now does this definitively rule out the possibility of spraying? Well, I think if anything, it may enhance that possibility because military aircraft (or aircraft that contract with the military) are what we would expect to be the culprit of chemtrails. But before we consider the unknown or more anomalous explanations like aerial spraying, I think it is important to consider the known first....and rule those out. Like I said, I think we may have ruled out the possibility of holding patterns by simple deductive reasoning...but have we really ruled out “Top Gun’s” explanation? Do we know for sure the altitude of these trails and the relative humidity and temperature that would rule out the possibility of normal contrail formation? Off hand, I would say that based on the information presented, there is no way to “ball park” the altitude. As we have shown, we do not have the trigonometric information available to guestimate altitude (for that we need at least one angle and side of a right triangle).....nor do we have radiosonde information for the day in question regarding temps and humidity aloft to prove that normal contrail formations at that altitude was not possible. Without this relevant information....it becomes impossible to rule out “Top Gun’s” explanation. By the same token, it also becomes impossible to rule out the possibility of chemical spraying. Both scenarios could likely happen in an MOA (Military Operations Area).

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cydoniaquest
nobody
nowhere 803 posts, Aug 2000
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posted 03-24-2001 03:31 PM
3t3l1,Pilots of low performance aircraft generally use an E6B computer or electronic version to make calculations when equipment on board the aircraft is minimal and not very sophisticated. Manual trigonometric calculations are rarely required nowdays with more sophisticated equipment on board like GPS, INS (inertial navigation systems) and flight computers that take into account, wind direction, crosswind component, aircraft airspeed and fuel requirements at the pressure altitude to be flown converted to true altitude and airspeed for groundspeed and range estimation. There are also graphs in the pilot's operating handbook to accurately arrive at this information based on aircraft performance, range and fuel consumption at altitude. Dirk was absolutely correct, by the way, as you keep failing to acknowledge...and this was an application of trigonometry that is not generally used by pilots.....but rather, more often used by surveyors with special equipment with laser range finders to find angles and accurate range. I think it is you 3t3ll who needs to go back and study the Pythagorean theorem and mathematical relationships of the right triangle...before you attack someone out of spite, who gave an absolutely correct answer.

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Dirk Digler
Senior Member
126 posts, Mar 2001
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posted 03-24-2001 03:43 PM
for mark sky and 3T3L1,could you please tell me the straight line distance from the camera to the point on the earth directly below the trail? by the way, thanks for the suggestion about taking more trig classes, but i think i'm alright. 
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Dirk Digler
Senior Member
126 posts, Mar 2001
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posted 03-24-2001 04:17 PM
ok, mark and 3T3L1 i need your help. http://www.ballparks.com/baseball/general/ads/ad061.htm
in this photo there is a cloud layer above the apartment buildings on the right side of the photo. now, the apartment buildings are 200 ft tall. they are 10000 ft from the camera ( i know this because i grew up at wrigley field)
using these figures please tell me the height of the clowds. thanks in advance 
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Dirk Digler
Senior Member
126 posts, Mar 2001
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posted 03-24-2001 04:30 PM
sorry guys, the link doesnt work very well. the picture i am referring to is the pic of wrigley field in chicago. it is in the 6th group of pics down the page
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mark sky
bin Rydin

SW coast of Oregon 1089 posts, Jun 2001
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posted 03-25-2001 04:28 PM
crosslink http://pub8.ezboard.com/fchemtrailschemtrails.showMessage?topicID=3156.topic Dirk, the distance you asked about in the circle trial photos is two miles. That is approximately in the center of the circles.
[Edited 1 times, lastly by mark sky on 03-25-2001] 
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Dirk Digler
Senior Member
126 posts, Mar 2001
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posted 03-25-2001 04:33 PM
mark sky,did you have a chance to "do the math", as you instructed me, on my above photo. it shouldnt be a problem for you. you should be able to use the exact same formulas as your "hill/trail" picture. 
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mark sky
bin Rydin

SW coast of Oregon 1089 posts, Jun 2001
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posted 03-25-2001 04:42 PM
no Dirk, it seems to site you directed me to "had fatal errors" shut down my computer, and caused a lot of problems perhaps i wont go there again thanks a lot
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Dirk Digler
Senior Member
126 posts, Mar 2001
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posted 03-25-2001 04:58 PM
sorry about that, it was a pretty graphics intensive site, lots of pics of baseball parks.i'll find another pic for you. if i knew how to post a pic here i would. 
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Dirk Digler
Senior Member
126 posts, Mar 2001
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posted 03-25-2001 05:08 PM
http://www.orlandosanfordairport.com/termxp10.htm ok Mark, here is another one for you. this page has 9 pics on it. the pic all the way on the bottom and to the right shows the front of a terminal building with an ominous looking trail above the terminal. notice that the trail comes down and "touches" the terminal just as your trail "touches" the hill. so, very similar picture to your so you should be able to use the same formulas to determine the height. here we go. the camera is 50 ft in front of the terminal. the terminal is 35 ft high. what is the height of the trails? thanks 
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Delphi
Mystic Warrior

S. Bossier, Louisiana 1583 posts, Mar 2001
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posted 03-25-2001 05:46 PM
Mark, I wouldn't check anymore of Dingles stuff if your computer messed up afterwards. We gotta use discernment here on the web, as you can't always know for sure, who's who, or what's what. And all those math problems thrown out there to everyone, it's not complicated to just plain look up. Most of us can trust our own eyes and instincts. Later dude. Joanne
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3T3L1
Differentiated Mouse Fibroblasts

Lubbock, Texas 1347 posts, Mar 2001
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posted 03-25-2001 05:48 PM
Dirk - What is the elevation (feet above sea level) of the terminal?
[Edited 1 times, lastly by 3T3L1 on 03-25-2001] 
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Dirk Digler
Senior Member
126 posts, Mar 2001
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posted 03-25-2001 06:00 PM
delphi, i assure you that i am not trying to crash anyones computer. give me a break. as a matter of fact, you shouldnt even need the picture, i provided all the data.3T3, the elevation of the ground is 55 ft above sea level.
[Edited 1 times, lastly by Dirk Digler on 03-25-2001] 
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Delphi
Mystic Warrior

S. Bossier, Louisiana 1583 posts, Mar 2001
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posted 03-25-2001 07:24 PM
Mark, You don't have to prove anything to anyone that works so hard to sow seeds of confusion, "muddy the waters" with a bunch of babble, all done to get us "off-track" and trying to get us to waste out time and energies answering them instead of keep busy in our endeavors and efforts. We have eyes, and instincts, and pictures are worth a 1,000 words...words that TPTB would like to "stifle" using any means they can. We are the ones out there taking the pictures and we know what we are witnessing, we can judge our distances and trust our powers of observation and that is what is worrisome and bothersome to TPTB. We have to stay "true to ourselves and to other "aware" individuals who see what is taking place and the rest, the rest are "talking heads" or "talking monkeys". Athiests wouldn't enjoy a religious website, why would non-believers want to waste their time here...must be for reasons we wouldn't like, negative ones.( By non-believers, meaning in reference to chemtrails). Take care.
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cydoniaquest
nobody
nowhere 803 posts, Aug 2000
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posted 03-25-2001 07:40 PM
Now wait a minute...I think Dirk should be allowed to complete his point. I think the point he is trying to make is that there is no way to mathematically compute height of trail based on the information given.Now if marksky has a way to do this, then I think it would be highly useful information, so we can get a quick and dirty estimate for contrail altitude in the future. Dirk raises very valid points.

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Dirk Digler
Senior Member
126 posts, Mar 2001
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posted 03-25-2001 08:51 PM
a quote from delphi"we can judge our distances and trust our powers of observation" the point i am making is that you can not judge these distances with any sort of accuracy. this is not a slight towards you, i can not either. it is hard for me tell from the ground if an airliner is at 25,000 ft or 35,000 ft mark sky has a picture that he claims is of low-level spraying. i believe he is mistaken. if you take that photo to "60 minutes" it will quickly be disregarded. i was trying to point this out by giving an almost identical math problem. i think if you look at it closely then you will see my point that you can not compute the height of his trail based on a hill that is in between the camera and the trail. apply his formulas to my photo and see what sort of answer you get. its a similar photo with the same known constants. it should work. 
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3T3L1
Differentiated Mouse Fibroblasts

Lubbock, Texas 1347 posts, Mar 2001
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posted 03-25-2001 09:13 PM
I wish I could draw this, but I'll just have to describe it. Here goes:First assumption--the camera is being held five feet above the ground, so the top of the terminal is 30 feet higher than the camera lens. Second assumption--that the contrail has formed at 35,000 feet. Top Gun says he has trailed at 20,000 feet, but we'll assume Mark's height for contrail formation is correct in this instance. The height of the camera and the height of the terminal above sea level are small fractions of 35,000 feet, so we shall ignore them. We shall also assume that the earth is flat. :-) Visualize a right triangle. The camera is located at one of the acute angles. Call the "opposite" side of the triangle 35 feet minus 5 feet, or 30 feet long. The "adjacent" side of the triangle runs parallel to the ground, from the building to the position of the camera, and it is 50 feet long. Visualize another, bigger, right triangle laid over the first one. The "opposite" side goes from the contrail to the ground, so it is 35,000 feet long. The "adjacent" side runs from the right angle to the position of the camera, parallel to the ground, and we'll call it "x" feet long. Because the top of the building and the contrail overlap from the perspective of the camera, the angle where the camera is located is the same in both triangles. This makes them "similar" triangles. Because the angle at the location of the camera is the same in both triangles, the ratio of opposite over adjacent in the big triangle is the same as the ratio of the opposite over adjacent in the little triangle. Thus, 35000 feet over "x" equals 30 feet over 50 feet. Do the math, and "x" equals 58333 feet. So if the cameraman travelled in a straight line for about 11 miles, the contrail would be directly overhead. The distance to the contrail along the hypotenuse of the right triangle would be about 12.9 miles. If you assume that contrails can form at 20,000 feet then your calculated distances to the contrail would be correspondingly shorter. 
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Dirk Digler
Senior Member
126 posts, Mar 2001
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posted 03-25-2001 09:41 PM
3T3,you just proved my point. you said "Second assumption--that the contrail has formed at 35,000 feet. " we are trying to find the height of the contrail. the contrail is the unknown. your formulas are correct but you are not using them correctly. use the same formulas and find THE HEIGHT OF THE CONTRAIL. dont assume anything about the contrail. in mark sky's famous "hill and low chemtrail" photo he used the known constants (distance to hill and height of hill) to determine the height of the trail. i am asking you to do the same thing with my photo. i have given you the same knowns (distance to building, height of buliling) that mark sky has given you. so you should be able to determine the height of the trail. you shouldnt have to assume antyhing. mark sky didnt assume anything. it is my contention that if the trail in mark sky's photo is at a low-level then the trail in my photo can be at a low-level. why do you assume my trail is at 35,000 ft? you didnt make the same assumption about his.
[Edited 2 times, lastly by Dirk Digler on 03-25-2001] 
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cydoniaquest
nobody
nowhere 803 posts, Aug 2000
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posted 03-25-2001 09:45 PM
AAAAH HA !!  I think I see what you're saying 3T3, (drew it out on paper to get the visual). But the problem with this equation is that you are still assuming facts not in evidence. For example, you assume the height of the contrail...but this is the very thing that the equation attempts to find out!. Now, we can divide 30 by 50 and take the inverse tangent to get the angle, but we still don't know the distance of the adjacent side of the larger right triangle to a point directly beneath the trail....and we still don't know the height of the contrail from a point directly underneath it. In other words, you have a common angle, but you still need at least one other side of the triangle to solve the problem. Again, you can't just assume the height of the contrail....this defeats the purpose of the whole thing!

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3T3L1
Differentiated Mouse Fibroblasts

Lubbock, Texas 1347 posts, Mar 2001
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posted 03-25-2001 11:38 PM
Technically, you're right, but the whole discussion started with Mark Sky's statement:"For these trails to be at 35000 feet elevation, they would have to be 50 to 60 miles in the distance." What he's saying is that there is a restricted range of altitudes at which true contrails can form. He has taken 35,000 feet as a reasonable average. If you take the values at either end of the permitted range, you come up with a range of distances at which true contrails would be located. He's saying that, if these are true contrails, they must be about 50 miles away from his camera. He doubts that he would have seen that much clarity and definition in the trails if they really had been that far away. Top Gun says that it's possible to see objects 150 miles away. I'm not a pilot, but from the fifth floor of our Medical School, it's easy to see 50 miles on most days. However, looking through that amount of atmosphere, I would be surprised to see true contrails that looked as clear and white as Mark's did. 
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Dirk Digler
Senior Member
126 posts, Mar 2001
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posted 03-26-2001 01:03 AM
i do not think that mark sky's statement of it has to be 60 miles away is correct, however, even if it is, it is still reasonable. you would be surprised, sometimes something will look 10 or 20 miles away. but you look down at the DME and it says 40.remember also, that the part of the trail that "has to be 60 miles away" is almost to the horizon (the part that touches the hill). very possible. "they must be about 50 miles away from his camera. He doubts that he would have seen that much clarity and definition in the trails" to give you an example. i do a lot of GA flying on the east coast of florida. on a good day you can see all the way to the other side of FLA. and this is at a relatively low altitude. this distance is roughly 110 nautical miles.
[Edited 1 times, lastly by Dirk Digler on 03-26-2001]

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3T3L1
Differentiated Mouse Fibroblasts

Lubbock, Texas 1347 posts, Mar 2001
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posted 03-26-2001 01:21 AM
I think Mark Sky used graph paper to estimate the distance. My trusty calculator gives a value closer to 38 miles.We'll just have to disagree on the effect of the atmosphere on the quality of "seeing." I would expect definition to degrade and the color to shift more and more toward blue when looking through that much air. 
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